\(A=\frac{3^{10}+1}{3^9+1}=\frac{3^{10}+3-2}{3^9+1}=\frac{3\left(3^9+1\right)-2}{3^9+1}=3-\frac{2}{3^9+1}\)
\(B=\frac{3^9+1}{3^8+1}=\frac{3^9+3-2}{3^8+1}=\frac{3\left(3^8+1\right)-2}{3^8+1}=3-\frac{2}{3^8+1}\)
Có \(3^9+1>3^8+1\)
\(\Rightarrow\frac{2}{3^9+1}< \frac{2}{3^8+1}\)
\(\Rightarrow3-\frac{2}{3^9+1}>3-\frac{2}{3^8+1}\)
\(\Rightarrow A>B\)
So sanh cac phan so sau:
A=\(\frac{3^{10}+1}{3^9+1}\)va B=\(\frac{3^9+1}{3^8+1}\)
So sanh A va B, biet :
a)\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};B=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
b)\(A=\frac{7^{10}}{1+7+7^2+...+7^9};B=\frac{5^{10}}{1+5+5^2+...+5^9}\)
hay so sanh m voi 1
M=\(\frac{1}{2!}+\frac{2}{3!}++......+\frac{9}{10!}\)
So sanh A va B.
Khong lam phep tinh hay so sanh:
a.[-1]*[-2]*[-3]*...*[-2009] voi 0
b.[-1]*[-2]*[-3]*...*[-10] voi 1*2*3*...*9*10
Cho A=1/2!+2/3!+......+8/9!+9/10!. so sanh A voi 1.Voi n!=1.2.3.....n(tích của n số tự nhiên khác 0 đầu tiên)
So sánh:
a, A= \(\frac{10^8+2}{10^8-1}\) ; B= \(\frac{10^8}{10^8-3}\)
b, A= \(\frac{8^{10}+1}{8^{10}-1}\) ; B=\(\frac{8^{10}-1}{8^{10}-3}\)
c, A= \(\frac{100^9+4}{100^9-1}\): B= \(\frac{100^9+1}{100^9-4}\)
\(Cho A=\frac{3^{10}+1}{3^9+1};B=\frac{3^9+1}{3^8+1}\)
so sánh A và B = 4 cách
hép mi
Cho A=1/2!+2/3!+......+8/9!+9/10!.so sanh A voi1.Voi n!=1.2.3.....n(tich cua n so tu nhien khac 0 dau tien)
