a) \(15=\sqrt{225}\)
\(\sqrt{235}=\sqrt{235}\)
vi \(225< 235\)nen \(\sqrt{225}< \sqrt{235}\)
vay \(15< \sqrt{235}\)
Câu b)
Ta có \(\sqrt{7}< \sqrt{9}\Leftrightarrow\sqrt{7}< 3\)
\(\sqrt{15}< \sqrt{16}\Leftrightarrow\sqrt{15}< 4\)
Cộng theo vế: \(\sqrt{7}+\sqrt{15}< 3+4\) hay \(\sqrt{7}+\sqrt{15}< 7\)
a,\(15=15\)
\(\sqrt{235}=15,32970972\)
\(\Rightarrow15< \sqrt{235}\)
b, \(\sqrt{7}+\sqrt{15}=6,518734657\)
\(7=7\)
\(\Rightarrow\sqrt{7}+\sqrt{15}< 7\)