Question

so sanh 4+\(\sqrt{33}va\sqrt{29}+\sqrt{14}\)

Answer 1

Ta có :

\(4+\sqrt{33}>4+\sqrt{25}=4+5=9\)

\(\sqrt{29}+\sqrt{14}< \sqrt{25}+\sqrt{9}=5+3=8\)

Vì \(9>8\) nên \(4+\sqrt{33}>\sqrt{29}+\sqrt{14}\)

Vậy \(4+\sqrt{33}>\sqrt{29}+\sqrt{14}\)

Answer 2

Sorry nhầm !!!! làm tại

\(\sqrt{29}+\sqrt{14}< \sqrt{33}+\sqrt{16}=\sqrt{33}+4\)

Vậy \(\sqrt{33}+4>\sqrt{29}+\sqrt{14}\)