\(729.24^{100}=3^6.\left(2^3.3\right)^{100}=3^{106}.2^{300}\)
\(4^{300}=2^{300}.2^{300}\)
Ta có: \(2^{300}>2^{212}=\left(2^2\right)^{106}=4^{106}>3^{106}\)
\(\Rightarrow2^{300}.2^{300}>2^{300}.3^{106}\Rightarrow4^{300}>729.24^{100}\)
Vậy \(2^{300}+3^{300}+4^{300}>729.24^{100}\)
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