\(A=98.\left(100+2\right)\)
\(A=98.100+98.2\)
\(B=100.\left(98+2\right)\)
\(B=100.98+100.2\)
VẬY A < B
A=98.102
=98.(100+2)
=98.100+98.2
B=100.100
=100.(98+2)
=100.98+100.2
Vì 98.100+98.2<100.98+100.2
=>A<B
Ta có: A=98.102
=> A=(100-2).102
=> A=100.102-2.102
Lại có: B=100.100
=> B=100.(102-2)
=> B=100.102-100.2
Vì 2.102>100.2 =>: B>A
\(A=98.102\Rightarrow A=\left(100-2\right)\left(100+2\right)=100^2-4\)
\(B=100^2\)
\(\Rightarrow A< B\)