\(\Leftrightarrow x^4-x^3+x^3-x^2-8x^2+8x+16x-16=0\\ \Leftrightarrow\left(x-1\right)\left(x^3+x^2-8x+16\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x^3+4x^2-3x^2-12x+4x+16\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x+4\right)\left(x^2-3x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=-4\\\left(x-\dfrac{3}{2}\right)^2+\dfrac{7}{4}=0\left(vô.n_o\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-4\end{matrix}\right.\)
Đúng 0
Bình luận (0)
