\(\left(x^2-2x\right)\left|3x-7\right|=0\)
\(\Rightarrow x^2-2x=0\) hoặc \(\left|3x-7\right|=0\)
+ \(x^2-2x=0
\)
\(x\left(x-2\right)=0\)
\(\int_{x-2=0\Rightarrow x=2}^{x=0}\)
+, |3x-7|=0
=> 3x-7=0
3x =7
x = 7:3
x = 7/3
Vậy \(x\in\left\{0,2,\frac{7}{3}\right\}\)