\(\frac{4.6^{14}}{9^7.8^5}=\frac{2^2.\left(2.3\right)^{14}}{\left(3^2\right)^7.\left(2^3\right)^5}=\frac{2^{16}.3^{14}}{3^{14}.2^{15}}=2\)
\(\frac{4.6^{14}}{9^7.8^5}=\frac{2^2.2^{14}.3^{14}}{\left(3^2\right)^7.\left(2^3\right)^5}=\frac{2^2.2^{14}.3^{14}}{3^{14}.2^{15}}=2\)
học tốt
\(\frac{2^2.\left(3.2\right)^{14}}{\left(3^2\right)^{14}.\left(2^3\right)^5}\)=\(\frac{2^2.3^{14}.2^{14}}{3^{28}.2^{15}}\)=\(\frac{2^2.2^{14}}{3^{14}.2^{15}}\)=\(\frac{2^{16}}{3^{14}.2^{15}}\)=\(\frac{2}{3^{14}}\)
Bài làm :
Ta có :
\(\frac{4.6^{14}}{9^7.8^5}=\frac{2^2.\left(2.3\right)^{14}}{\left(3^2\right)^7.\left(2^3\right)^5}=\frac{2^{16}.3^{14}}{3^{14}.2^{15}}=2\)