P= (1-1/1+2).(1-1/1+2+3).(1-1/1+2+3+4).....(1/1+2+3+4+...+100)
P=0
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Rut gon phan so sau : (-1/2)^3-(3/4)^3.(-2)^2 phần 2.(-1)^5+(3/4)^2-3/8
A=1/4+1/42+1/43+.....+1/499
a) Rut gon A
b) So sanh A voi 1/3
rut gon bieu thuc
B=1/2+(1/2)^2+(1/2)^3+...+(1/2)^99
Bai 1: Rut gon bieu thuc sau
B=(2/3)^3×(-3/4)^4×(-1)^5/(2/5)^2 × (-5/12)^3
Bai 2: Tim ia tri bieu thuc sau
M= 512- 512/2- 512/2^2- 512/2^2 - 512/2^3...512/2^10
Rut gon bieu thuc
(x+1)2 - (x-1)2 - 3. (x+1). (x-1)
rut gon bthuc sau;/a/:a
/a/.a
3.(x-1)-2./x+3/
2./x-3/-/4x-1/
Rut gon 2|2x-1| - 3|2x+3|
Rut gon \(B=\left(1-\frac{3}{2.4}\right)\left(1-\frac{3}{3.5}\right)\left(1-\frac{3}{4.6}\right)....\left(1-\frac{3}{n\left(n+2\right)}\right)\)
rut gon
A=1-6+62-63+...-699+6100