a)\(\frac{3.21}{14.15}=\frac{1.3}{2.5}=\frac{3}{10}\)
b)\(\frac{49+7.49}{49}=\frac{49.\left(1+7\right)}{49}=\frac{8}{1}=8\)
a)\(\frac{3.21}{14.15}=\frac{1.3}{2.5}=\frac{3}{10}\)
b)\(\frac{49+7.49}{49}=\frac{49.\left(1+7\right)}{49}=1.8=8\)
a,\(\frac{3.21}{14.15}=\frac{3.3.7}{2.7.3.5}=\frac{3}{10}\)
b,\(\frac{49+7.49}{49}=\frac{49.\left(1+7\right)}{49}=1.8=8\)
\(\frac{3.21}{14.15}=\frac{3.3.7}{7.2.5.3}=\frac{3}{10}\)
\(\frac{49+7.49}{49}=\frac{8.49}{49}=8\)
GIẢI :
a) \(\frac{3\cdot21}{14\cdot15}=\frac{3\cdot3\cdot7}{2\cdot7\cdot3\cdot5}=\frac{3}{2\cdot5}=\frac{3}{10}\) ;
b) \(\frac{49+7\cdot49}{49}=\frac{49 (1+7)}{49}=1+7=8\).