5xy\(\sqrt{\frac{25x^2}{y^6}}\)= 5xy ./\(\frac{5x}{y^3}\)/ = \(\orbr{\begin{cases}5xy.\frac{-5x}{y^3}\\5xy.\frac{5x}{y^3}\end{cases}}\)=\(\orbr{\begin{cases}\frac{-25x^2}{y^2}\\\frac{25x^2}{y^2}\end{cases}}\)
bang 12 hoac 49 nha minh ko biet no dung hay ko