Question

rút gọn B:

B=\(\dfrac{2\sqrt{X}}{\sqrt{X}-2}-\dfrac{X+6\sqrt{X}-4}{X-\sqrt{X}-2}\)

Answer 1

B= \(\dfrac{2\sqrt{x}}{\sqrt{x}-2}-\dfrac{x+6\sqrt{x}}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-2\right)}\)

B= \(\dfrac{2\sqrt{x}\left(\sqrt{x}+1\right)-x-6\sqrt{x}+4}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-2\right)}\)

B= \(\dfrac{2x+2\sqrt{x}-x-6\sqrt{x}+4}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-2\right)}\)

B= \(\dfrac{x-4\sqrt{x}+4}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-2\right)}\) 

B= \(\dfrac{\left(\sqrt{x}-2\right)^2}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-2\right)}\)

B = \(\dfrac{\sqrt{x}-2}{\sqrt{x}+1}\)