Question

rút gọn A : 
A=(\(\frac{\mathrm 2+x }{\mathrm 2- x}\)-\(\frac{\mathrm 4x^2}{\mathrm x^2 -4}\)-\(\frac{\mathrm 2-x}{\mathrm 2+x}\)):(\(\frac{\mathrm x^2-3x}{\mathrm 2x^2-x^3}\))

Answer 1

\(A=\left(\frac{x+2}{2-x}-\frac{4x^2}{x^2-4}-\frac{2-x}{x+2}\right):\left(\frac{x^2-3x}{2x^2-x^3}\right)\)

\(A=\left[\frac{\left(x+2\right)^2}{4-x^2}+\frac{4x^2}{4-x^2}-\frac{\left(2-x\right)^2}{4-x^2}\right]:\left[\frac{x\left(x-3\right)}{x^2.\left(2-x\right)}\right]\)

\(A=\left[\frac{x^2+4x+4+4x^2-4+4x-x^2}{4-x^2}\right]:\left[\frac{x-3}{x\left(2-x\right)}\right]\)

\(A=\frac{4x^2+8x}{4-x^2}:\frac{x-3}{x\left(2-x\right)}\)

\(A=\frac{4x\left(x+2\right)}{\left(2-x\right)\left(x+2\right)}.\frac{x\left(2-x\right)}{x-3}\)

\(A=\frac{4x^2}{x-3}\)

Answer 2

giúp mình với !!!

Answer 3

cảm ơn bạn !