a, b, c: \(\hept{\begin{cases}\frac{3}{6}=\frac{3\times9}{6\times9}=\frac{27}{54};\frac{4}{9}=\frac{4\times6}{9\times6}=\frac{24}{54}\\\frac{10}{9}=\frac{10\times7}{9\times7}=\frac{70}{63};\frac{5}{7}=\frac{5\times9}{7\times9}=\frac{45}{63}\\\frac{3}{5};\frac{56}{40}=\frac{56:8}{40:8}=\frac{7}{5}\end{cases}}\)
a) \(\frac{3}{6}\)và\(\frac{4}{9}\)
Ta có: Mẫu số chung: 18
\(\Rightarrow\frac{3}{6}=\frac{3\cdot3}{6\cdot3}=\frac{9}{18};\frac{4}{9}=\frac{4\cdot2}{9\cdot2}=\frac{8}{18}\)
b) \(\frac{10}{9}\)và \(\frac{5}{7}\)
Ta có: Mẫu số chung: 63
\(\Rightarrow\frac{10}{9}=\frac{10\cdot7}{9\cdot7}=\frac{70}{63};\frac{5}{7}=\frac{5\cdot9}{7\cdot9}=\frac{45}{63}\)
c) \(\frac{3}{5}\)và \(\frac{56}{40}\)
Ta có: Mẫu số chung: 5
\(\Rightarrow\frac{3}{5}=\frac{3}{5};\frac{56}{40}=\frac{56:8}{40:8}=\frac{7}{5}\)
