\(Q=\left(-3\right)+\left(-4\right)+\left(-5\right)+...+\left(-40\right)\\ \Rightarrow Q=-\left(3+4+5+...+40\right)\\ \Rightarrow Q=-817\)
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So sánh
\(A=40+\frac{3}{8}+\frac{7}{8^2}+\frac{5}{8^3}+\frac{32}{8^5}\)
\(B=\frac{24}{8^2}+40+\frac{5}{8^2}+\frac{40}{8^4}+\frac{5}{8^4}\)
Cho:
\(A=40+\frac{3}{8}+\frac{7}{8^2}+\frac{5}{8^3}+\frac{32}{8^5}\)
\(B=\frac{24}{8^2}+40+\frac{5}{8^2}+\frac{40}{8^4}+\frac{5}{8^4}\)
Hãy so sánh A và B
cho A =\(40+\frac{3}{8}+\frac{7}{8^2}+\frac{5}{8^3}+\frac{32}{8^5}\)
B=\(\frac{24}{8^2}+40+\frac{5}{8^2}+\frac{40}{8^4}+\frac{5}{8^4}\)
So sánh A và B
\(\frac{11}{40}+\frac{4}{5}-\text{|}\frac{3}{4}-1\frac{5}{12}\text{|}=\frac{3}{20}-x\)
\(\left(0,125+40\%-\frac{3}{40}\right)\):\(\orbr{\begin{cases}\\\end{cases}11\frac{3}{7}+8\frac{1}{2}-\left(\frac{13}{12}-5\frac{4}{7}\right)}\)
\(-\frac{4}{5}-|\frac{3}{4}-1\frac{1}{8}|=\frac{7}{20}-x+\frac{3}{-40}\)
\(\left(\frac{1}{8}-\frac{1}{5}+\frac{3}{40}\right):\frac{4}{5}\)
tìm x biết
\(\frac{3}{4}\). x + 40% = \(\frac{-1}{4}\)
\(\frac{1}{2}\)- \(\frac{2}{5}\).x = \(\frac{-1}{3}\)
|x - 1| = 2^3+ (-5)
25) chứng tỏ rằng
a)\(5^{2015}+5^{2014}+5^{2013}⋮31\)
b)\(4^{39}+4^{40}+4^{41}⋮28\)
c)\(1+7+7^2+7^3+..+7^{100}+7^{101}⋮8\)