Question

ptđttnt 
x³-9x²+6x+16
1 câu thôi giúp nhá

Answer 1

nhẩm x=-1 là nghiệm

\(\left(x+1\right)\left(x^2-10x+16\right)=\left(x+1\right)\left[\left(x-5\right)^2-9\right]=\left(x+1\right)\left(x-8\right)\left(x-2\right)\)

Answer 2

mk mới hok lp 5

xin lỗi bn nhé

Answer 3

mình chịu

Answer 4

Ta có:

\(\left(x+1\right)\left(x^2-10x+16\right)=\left(x+1\right)\left(x^2-8x-2x+16\right)\)

\(=\left(x+1\right)\left(\left(x^2-8x\right)-\left(2x-16\right)\right)\)

\(=\left(x+1\right)\left(x\left(x-8\right)-2\left(x-8\right)\right)\)

\(=\left(x+1\right)\left(x-8\right)\left(x-2\right)\)