Question

PTĐTTNT theo phương pháp tách hạng tử

a,x^2-5x+6

b,3x^2+9x-30

c,x^2-3x+2

Answer 1

a, x²-5x+6=(x²-2x)-(3x-6)=x(x-2)-3(x-2)=(x-2)(x-3)

b, 3x²+9x-30=(3x²-6x)+(15x-30)=3x(x-2)+15(x-2)=3(x-2)(x+5)

c, x²-3x+2=(x²-x)-(2x-2)=x(x-1)-2(x-1)=(x-1)(x-2)

Answer 2

a, x^2-5x+6=x^2-2x-3x+6=(x^2-2x)-(3x-6)=x(x-2)-3(x-2)=(x-3)(x-2)

b, 3x^2+9x-30=3x^2-6x+15x-30=(3x^2-6x)+(15x-30)=3x(x-2)+3(x-2)=(3x+3)(x-2)

c, x^2-3x+2=x^2-x-2x+2=(x^2-x)-(2x-2)=x(x-1)-2(x-1)=(x-2)(x-1)

Answer 3

câu b mik lm nhầm nhé