Question

Pt đa thức thành nhân tử :

b, x mũ 2 - y mũ 2 + z mũ 2 - t mũ 2 - 2xz + 2yt

Answer 1

\(x^2-y^2+z^2-t^2-2xz+2yt=\)

\(=\left(x^2-2xz+z^2\right)-\left(y^2-2yt+t^2\right)=\)

\(=\left(x-z\right)^2-\left(y-t\right)^2=\)

\(=\left[\left(x-z\right)-\left(y-t\right)\right]\left[\left(x-z\right)+\left(y-t\right)\right]\)

Answer 2

   \(x^2-y^2+z^2-t^2-2xz+2yt\)

\(=\left(x^2-2xz+z^2\right)-\left(y^2+2yt+t^2\right)\)

\(=\left(x-z\right)^2-\left(y-t\right)^2\) 

\(=\left(x-z+y-t\right)\times\left(x-z-y+t\right)\)

Answer 3

\(x^2-y^2+z^2-t^2-2xz+2yt\)

\(=x^2-2xz+z^2-\left(y^2-2yt+t^2\right)\)

\(=\left(x-z\right)^2-\left(y-t\right)^2\)

\(=\left(x-z+y-t\right)\left(x-z-y+t\right)\)

Answer 4

x2−y2+z2−t2−2xz+2yt = (x−z+y−t)(x−z−y+t)