Question

phân tích x^5+x+1 thành nhân tử

Answer 1

Tham khảo!

x5+x-1 x5+x-1 = x5-x4+x3+x4-x3+x2-x2+x-1          

 = x3(x2-x+1)+x2(x2-x+1)-(x2-x+1)          

 = (x2-x+1)(x3+x2-1)
 

Answer 2

x5+x-1 x5+x-1 = x5-x4+x3+x4-x3+x2-x2+x-1          

 = x3(x2-x+1)+x2(x2-x+1)-(x2-x+1)          

 = x2-x+1x3+x2-1
 

  

Answer 3

x5+x-1 x5+x-1 = x5-x4+x3+x4-x3+x2-x2+x-1

= x3(x2-x+1)+x2(x2-x+1)-(x2-x+1)

= (x2-x+1)(x3+x2-1)