Question

phân tích thành nhân tử

x(x+4)(x+6)(x+10)+128

Answer 1

\(x\left(x+4\right)\left(x+6\right)\left(x+10\right)+128\)

\(=\left(x^2+10x\right)\left(x^2+10x+24\right)+128\)

\(=\left(x^2+10x\right)^2+24\left(x^2+10x\right)+128\)

\(=\left(x^2+10x\right)^2+8\left(x^2+10x\right)+16\left(x^2+10x\right)+128\)

\(=\left(x^2+10x+8\right)\left(x^2+10x+16\right)\)

\(=\left(x^2+10x+8\right)\left(x+2\right)\left(x+8\right)\)