Câu hỏi của Phan Thị Mỹ Duyên

Question

phân tích thành nhân tửa, (3x+1)2-(x+1)2b,(x-1)3+(x+2)3c,7x2-7xy-4x+4yd, x2-x-y2-y

Nguyễn Thị BÍch Hậu · Accepted Answer

a) $=\left(3x+1-x-1\right)\left(3x+1+x+1\right)=2x\left(4x+2\right)=4x\left(2x+1\right)$b) $\left(x-1+x+2\right)\left[\left(x-1\right)^2-\left(x-1\right)\left(x+2\right)+\left(x+2\right)^2\right]=\left(2x+1\right)\left(x^2-2x+1-x^2-x+2+x^2+4x+4\right)$$=\left(2x+1\right)\left(x^2+x+7\right)$c) $=\left(x^2-y^2\right)-\left(x+y\right)=\left(x+y\right)\left(x-y\right)-\left(x+y\right)=\left(x+y\right)\left(x-y-1\right)$Câu trả lời: a) $=\left(3x+1-x-1\right)\left(3x+1+x+1\right)=2x\left(4x+2\right)=4x\left(2x+1\right)$b) $\left(x-1+x+2\right)\left[\left(x-1\right)^2-\left(x-1\right)\left(x+2\right)+\left(x+2\right)^2\right]=\left(2x+1\right)\left(x^2-2x+1-x^2-x+2+x^2+4x+4\right)$$=\left(2x+1\right)\left(x^2+x+7\right)$c) $=\left(x^2-y^2\right)-\left(x+y\right)=\left(x+y\right)\left(x-y\right)-\left(x+y\right)=\left(x+y\right)\left(x-y-1\right)$

Minh Triều · Answer

mjk chán wa ko muốn giảiCâu trả lời: mjk chán wa ko muốn giải

Ran Mori · Answer

$x^2-x-y^2-y$$=\left(x-y\right)\left(x+y\right)-\left(x+y\right)$$=\left(x+y\right)\left(x-y-1\right)$hk tốtCâu trả lời: $x^2-x-y^2-y$$=\left(x-y\right)\left(x+y\right)-\left(x+y\right)$$=\left(x+y\right)\left(x-y-1\right)$hk tốt

a) 5x – 15y	b) 5x²y² + 15x²y + 30xy²
c) x³ – 2x²y + xy² – 9x	d) x(x² – 1) + 3(x² – 1)
e) x² – 10x + 25	g) x² – 64
h) (x + y)² – (x² – y²)	i) 5x² + 5xy – x – y
k) x² – 25 + y² + 2xy	l) 2xy – x² – y² + 16
m) (x – 2)(x – 3) + (x – 2) - 1	n) 3(x – 1) + 5x( 1 – x)
p) 12y(2x – 5) + 6xy(5 – 2x)	q) ax – 2x – a² + 2a

a) a² – b² – 2a + 1	b) x² – 2x – 4y² – 4y
c) x² + 4x – y² + 4	d) x⁴ – 1
e) x⁴ + x³ + x² + x	g) a² + 2ab + b² – ac - bc

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