Question

Phân tích thành nhân tử `xy(a^2 +b^2) -ab(x^2 +y^2)`

Answer 1

\(=a^2xy+b^2xy-abx^2-aby^2\)

\(=ay\left(ax-by\right)-bx\left(ax-by\right)\)

\(=\left(ax-by\right)\left(ay-bx\right)\)

Answer 2

xy(a²+b²)-ab(x²+y²)

= xya²+xyb²-abx²-aby²

=(xya²-aby²)-(abx²-xyb²)

=ay(xa-by)-xb(xa-by)

=(xa-by)(ay-xb)