Question

Phân tích đa thức thành nhân tử:

\(x^3-8+2x\left(x-2\right)\)

Answer 1

\(x^3-8+2x\left(x-2\right)\\ =\left(x-2\right)\left(x^2+2x+4\right)+2x\left(x-2\right)\\ =\left(x-2\right)\left(x^2+2x+4+2x\right)=\left(x-2\right)\left(x^2+4x+4\right)\\ =\left(x-2\right)\left(x+2\right)^2\)

Answer 2

=\(\left(x-2\right)\left(x^2+2x+4\right)+2x\left(x-2\right)\)

=\(\left(x-2\right)\left(x^2+4x+4\right)\)

=\(\left(x-2\right)\left(x+2\right)^2\)