\(x^3-5x^2+8x-4=x^3-x^2-4x^2+4x+4x-4\)
\(=x^2.\left(x-1\right)-4x.\left(x-1\right)+4\left(x-1\right)=\left(x-1\right)\left(x^2-4x+4\right)\)
\(=\left(x-1\right)\left(x-2\right)^2\)
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