Question

phân tích đa thức thành nhân tử

\(x^2-n^2-2xy+y^2-m^2+2mn\)

Answer 1

Easy \(x^2-n^2-2xy+y^2-m^2+2mn\)

\(=\left(x^2-2xy+y^2\right)-\left(n^2-2mn+m^2\right)\)

\(=\left(x-y\right)^2-\left(n-m\right)^2\)

\(=\left(x-y-n+m\right)\left(x-y+n-m\right)\)

Answer 2

\(x^2-n^2-2xy+y^2-m^2+2mn\)

\(=\left(x^2-2xy+y^2\right)-\left(n^2-2mn+m^2\right)\)

\(=\left(x-y\right)^2-\left(n-m\right)^2\)

\(=\left(x-y-n+m\right)\left(x-y+n-m\right)\)

Answer 3

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Nguồn by : Hỏa Long Natsu