a, \(x^3-6x^2+9x\)
\(=x\left(x^2-6x+9\right)\)
\(=x \left(x-3\right)\)
Câu b, c cũng tượng tự nha bn , dễ mà
#hoc_tot#
b) \(x^2-2xy+3x-6y=x\left(x-2y\right)+3\left(x-2y\right)=\left(x-2y\right)\left(x+3\right)\)
c)\(x^2-8x+7=x^2-x-7x+7=x\left(x-1\right)-7\left(x-1\right)=\left(x-1\right)\left(x-7\right)\)
a)\(x^3-6x^2+9x=x\left(x^2-2\cdot x\cdot3+3^2\right)=x\left(x-3\right)^2\)
~ Chúc bạn học tốt ~
a,= \(x\left(x-3\right)^2\)
b, = \(x\left(x-2y\right)+3\left(x-2y\right)\)
= \(\left(x-2y\right)\left(x+3\right)\)
c, = \(x^2-7x-x+7\)
= \(x\left(x-7\right)-\left(x-7\right)\)
= \(\left(x-1\right)\left(x-7\right)\)
hok tốt
............
a) x3 − 6x2+ 9x
= x(x2 − 6x + 9)
= x(x − 3)
b) x2-2xy+3x-6y
= x(x-2y)+3(x-2y)
= (x-2y)(x+3)
c) x2-8x+7
= x2-7x-x+7
= x(x-7)-(x-7)
= (x-1)(x-7)
thành nhân tử ta được:
)(9x2-x+
) 
)(9x2+x+
.
.