Question

Phân tích đa thức thành nhân tử: 

x^2+4xy+4y^2-4z^2-1-4z

Giúp mik vs đc ko???

Answer 1

= ( x² + 4xy +4y² ) - ( 4z² +4z +1 ) 
= ( x + y )² - [ (2z)² - 2z.1 +1²)]
= ( x + y )²  - (2z+1)²
= ( x + y - 2z - 1 ).( x + y + 2z + 1 )
 

Answer 2

=\(x^2+2.x.2y+\left(2y\right)^2-\left[\left(2z\right)^2+2.2z.1+1^2\right]=\left(x+2y\right)^2-\left(2z+1\right)^2=\left(x+2y+2z+1\right)\left(x+2y-2z-1\right)\)