Question

Phân tích đa thức thành nhân tử : x²-2xy+x+3xz-2y+3z

Answer 1

x² - 2xy + x + 3xz - 2y + 3z

= x² - 2xy + x - 2y + 3xz + 3z

= x ( x - 2y ) + ( x - 2y ) + 3z( x + 1 )

= ( x - 2y ) ( x + 1 ) + 3z ( x + 1 )

= ( x + 1 ) ( x - 2y + 3z )

Answer 2

\(x^2-2xy+x+3xz-2y+3z\)

\(=\left(x^2+x\right)+\left(-2xy-2y\right)+\left(3xz+3z\right)\)

\(=x\left(x+1\right)-2y\left(x+1\right)+3z\left(x+1\right)\)

\(=\left(x+1\right)\left(x-2y+3z\right)\)