\(\left(x-8\right)^2+36=x^2-16x+64+36=x^2-16x+100>0\)
xem lại đề
(x-8)2+ 36
(x-8)2 +62
(x-8) +6
x = 8+6=14
\(\left(x-8\right)^2+36\)
\(=-\left[\left(x+8\right)^2-6^2\right]\)
\(=\left(x+8+6\right)\left(x +8-6\right)\)
\(=\left(x+14\right)\left(x+2\right)\)