Question

Phân tích đa thức sau thành nhân tử

x²-9-4*(x+3)

Answer 1

\(x^2-9-4\left(x+3\right)\)

\(=\left(x-3\right)\left(x+3\right)-4\left(x+3\right)\)

\(=\left(x+3\right)\left(x-3-4\right)\)

\(=\left(x+3\right)\left(x-7\right)\)

Answer 2

x² - 9 - 4(x + 3)

= (x² - 9) - 4(x + 3)

= (x² - 3²) - 4(x + 3)

= (x - 3) (x + 3) - 4(x + 3)

= (x + 3) (x -  3 - 4)

= (x + 3)  ( x - 7)

ko bít đúng ko !! 547467474856856856856835675743634634645765876976946426436

Answer 3

thank mấy bạn nha

Answer 4

x^2-9-4*(x+3)

=(x-3)(x+3)-4(x+3)

=(x+3)(x-3+4)

=(x+3)(x+1)

Answer 5

(x-3)(x-7)