Question

Phân tích đa thức sau thành nhân tử: 5x² - 19x - 4

Answer 1

\(5x^2-19x-4\)

\(=\left(5x^2-20x\right)+\left(x-4\right)\)

\(=5x\left(x-4\right)+\left(x-4\right)\)

\(=\left(x-4\right)\left(5x+1\right)\)

Answer 2

\(5x^2-19x-4=5x^2+x-20x-4\)

\(=x\cdot\left(5x+1\right)-4\cdot\left(5x+1\right)\)

\(=\left(5x+1\right)\cdot\left(x-4\right)\)

Answer 3

cám ơn ạ <3

Answer 4

Mk ko bt có đúng ko nữa:

\(5x^2-19x-4\)

\(=5x^2+x-20x-4\)

\(=x.\left(5x+1\right)-4.\left(5x+1\right)\)

\(=\left(5x+1\right).\left(x-4\right)\)

Rất vui vì giúp đc bạn !!!

Answer 5

5x^2 - 19x - 4

= 5x^2 + x - 20x - 4

= (5x^2 + x) - (20x + 4)

= x(5x + 1) - 4(5x + 1)

= (5x + 1)(x - 4)