Question

Phân tích các đa thức sau thành nhân tử

Answer 1

d: \(9x^2-25=\left(3x-5\right)\left(3x+5\right)\)

e: \(16x^2-4y^2=4\left(4x^2-y^2\right)=4\left(2x-y\right)\left(2x+y\right)\)

f: \(\left(x+\dfrac{1}{4}\right)^2=x^2+\dfrac{1}{2}x+\dfrac{1}{16}\)

Answer 2

\(d,9x^2-25=\left(3x-5\right)\left(3x+5\right)\\ e,16x^2-4y^2=\left(4x-2y\right)\left(4x+2y\right)=4\left(2x-y\right)\left(2x+y\right)\)

Answer 3

d: \(9x^2-25=\left(3x-5\right)\left(3x+5\right)\)

e: \(16x^2-4y^2=4\left(4x^2-y^2\right)=4\left(2x-y\right)\left(2x+y\right)\)

Answer 4

\(9x^2-25\)

\(=\)\((3x)^2-5^2\)

\(=(3x-5)(3x+5)\)