Question

phân tích các đa thức sau thành nhân tử:

x³$-$2x²$-$x+2

x2+6x$-$y2+9

Answer 1

\(x^3-2x^2-x+2\)

\(=x^2\left(x-2\right)-\left(x-2\right)\)

\(=\left(x^2-1\right)\left(x-2\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(x-2\right)\)

\(x^2+6x-y^2+9\)

\(=\left(x^2+6x+9\right)-y^2\)

\(=\left(x+3\right)^2-y^2\)

\(=\left(x+3-y\right)\left(x+3+y\right)\)

Answer 2

đề bài kiểu gì vậy

Answer 3

ghi de bai gi cut ngủn hieu chet lien

Answer 4

x³-2x²-x+2

=(x³-2x²)-(x-2)

=x²(x-2)-(x-2)

=(x-2)(x²-1)

x²+6x-y2+9

=(x²+6x+9)-y²

=(x+3)²-y²

=(x+3-y)(x+3+y)