Question

phân tích 

2xy+3z+6y+xz

 

Answer 1

\(=\left(2xy+6y\right)+\left(3z+xz\right)=2y\left(x+3\right)+z\left(3+x\right)=\left(2y+z\right)\left(x+3\right)\)

Answer 2

Cách 1.

Ta có: 2xy + 3z + 6y + xz = (2xy + xz) + (3z + 6y)

= x(2 y + z)+3(z + 2 y) = (z + 2y)(x + 3).

Cách 2.

Ta có: 2xy + 3z + 6y + xz = (2x1/ + 6y) + (3z + xz)

= 2y(x + 3) + z(3 + x) = (z + 2y)(x + 3).

Answer 3

2xy+3z+6y+xz

=(2xy+6y)+(3z+xz)

=2y(x+3)+z(x+3)

=(x+3)(2y+z)