Question

phân tchs đa thức thành nhân tử

x^3+2x^2-3x-6

2a^2c^2-2abc+bd-acd

5x^2(x-1)-10xy(x-1)-5y^2(1-x)

x^5-x^4y-xy^4+y^5

x^2-6xy+9y^2-9

Answer 1

a)      \(x^3+2x^2-3x-6\)

\(=x^2\left(x+2\right)-3\left(x+2\right)\)

\(=\left(x^2-3\right)\left(x+2\right)\)

b)     \(5x^2\left(x-1\right)-10xy\left(x-1\right)-5y^2\left(1-x\right)\)

\(=5x^2\left(x-1\right)-10xy\left(x-1\right)+5y^2\left(x-1\right)\)

\(=\left(5x^2-10xy+5y^2\right)\left(x-1\right)\)

\(=5\left(x^2-2xy+y^2\right)\left(x-1\right)\)

\(=5\left(x-y\right)^2\left(x-1\right)\)

c)   \(x^2-6xy+9y^2-9\)

\(=\left(x-3\right)^2-3^2\)

\(=\left(x-3-3\right)\left(x-3+3\right)\)

\(\left(x-6\right)x\)

cái thứ 2 và 5 ko hiểu j nên ko làm

Answer 2

mk làm lun nha 

1,= x(x^2-3)+2(x^2-3)

= (x+2)(x^2-3)

2.= 2ac(a-b)- d(a-b)

= (2ac-d)(a-b)

3,= (x-1)(5x^2-10xy+5x^2)

= 5(x-1)(x^2-2xy+y^2)

= 5(x-1)(x-y)^2

4, = (x^2-6xy+9y^2)-9

= (x-3y)^2-3^2

= (x-3y+3)(x-3y-3)

Answer 3

hihi xl bn nha câu 4 đây nha bn := x(x^4-y^4)-y(x^4-y^4)

= (x-y)(x^4-y^4)

mk làm xog rồi nhé

Answer 4

4, = x(x^4-y^4)- y (x^4-y^4)

= (x-y)(x^4-y^4)

Answer 5

5. \(x^2-6xy+9y^2-9\)\(=\left(x-3y\right)^2-9\)\(=\left(x-3y-3\right)\left(x-3y+3\right)\)