a) \(x^3+2x^2-3x-6\)
\(=x^2\left(x+2\right)-3\left(x+2\right)\)
\(=\left(x^2-3\right)\left(x+2\right)\)
b) \(5x^2\left(x-1\right)-10xy\left(x-1\right)-5y^2\left(1-x\right)\)
\(=5x^2\left(x-1\right)-10xy\left(x-1\right)+5y^2\left(x-1\right)\)
\(=\left(5x^2-10xy+5y^2\right)\left(x-1\right)\)
\(=5\left(x^2-2xy+y^2\right)\left(x-1\right)\)
\(=5\left(x-y\right)^2\left(x-1\right)\)
c) \(x^2-6xy+9y^2-9\)
\(=\left(x-3\right)^2-3^2\)
\(=\left(x-3-3\right)\left(x-3+3\right)\)
\(\left(x-6\right)x\)
cái thứ 2 và 5 ko hiểu j nên ko làm
mk làm lun nha
1,= x(x^2-3)+2(x^2-3)
= (x+2)(x^2-3)
2.= 2ac(a-b)- d(a-b)
= (2ac-d)(a-b)
3,= (x-1)(5x^2-10xy+5x^2)
= 5(x-1)(x^2-2xy+y^2)
= 5(x-1)(x-y)^2
4, = (x^2-6xy+9y^2)-9
= (x-3y)^2-3^2
= (x-3y+3)(x-3y-3)
hihi xl bn nha câu 4 đây nha bn := x(x^4-y^4)-y(x^4-y^4)
= (x-y)(x^4-y^4)
mk làm xog rồi nhé
4, = x(x^4-y^4)- y (x^4-y^4)
= (x-y)(x^4-y^4)
5. \(x^2-6xy+9y^2-9\)\(=\left(x-3y\right)^2-9\)\(=\left(x-3y-3\right)\left(x-3y+3\right)\)