Ta có: nHCl = 1.1 = 1 (mol)
\(\Rightarrow m_{ddHCl}=\dfrac{1.36,5}{36,6\%}=\dfrac{18250}{183}\left(g\right)\)
\(\Rightarrow V_{ddHCl}=\dfrac{m_{ddHCl}}{1,1}\approx90,66\left(ml\right)\)
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