c) Ta có: \(\dfrac{1}{P}=\dfrac{4}{5}\)
\(\Rightarrow1:\left(\dfrac{3}{\sqrt{x}+1}\right)=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{3}{\sqrt{x}+1}=\dfrac{5}{4}\)
\(\Leftrightarrow5\left(\sqrt{x}+1\right)=12\)
\(\Leftrightarrow\sqrt{x}-1=\dfrac{12}{5}\)
\(\Leftrightarrow\sqrt{x}=\dfrac{12}{5}+1\)
\(\Leftrightarrow\sqrt{x}=\dfrac{17}{5}\)
\(\Leftrightarrow x=\left(\dfrac{17}{5}\right)^2=\dfrac{289}{25}\)
Sửa đề : (xem lại)
`c)1/P=4/3`
`=>P=3/4`
`<=>3/(\sqrtx+1)=3/4`
`=>\sqrtx+1=4`
`=>\sqrtx=3`
`=>x=9(t/m)`
Vậy với `x=9` thì `1/P=4/3`