\(a,P=\dfrac{2x^2-1}{x^2+x}-\dfrac{x-1}{x}+\dfrac{3}{x+1}\left(x\ne0;x\ne-1\right)\\ P=\dfrac{2x^2-1-x^2+1+3x}{x\left(x+1\right)}=\dfrac{x\left(x+3\right)}{x\left(x+1\right)}=\dfrac{x+3}{x+1}\\ b,P=0\Leftrightarrow x+3=0\Leftrightarrow x=-3\left(tm\right)\\ c,x^2-x=0\Leftrightarrow x\left(x-1\right)=0\Leftrightarrow x=1\left(x\ne0\right)\\ \Leftrightarrow P=\dfrac{1+3}{1+1}=\dfrac{4}{2}=2\)