Question

P=12(5^2 +1)(5^4+1)(5^8+1)(5^16+1)

Answer 1

\(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^{16}-1\right)\left(5^{16}+1\right)\)

\(P=\frac{1}{2}\left(5^{32}-1\right)\)

\(P=\frac{5^{32}-1}{2}\)