Bài 1:
a: \(=936-508+8\cdot\left(5^2+1\right)=428+8\cdot26=636\)
b: \(=\dfrac{2^6\cdot2\cdot3^2+2^7}{2^6\cdot5^2-2^6\cdot3}=\dfrac{2^7\cdot10}{2^6\cdot22}=\dfrac{10}{11}\)
c: \(=-\left(\dfrac{1}{2}+\dfrac{1}{6}+...+\dfrac{1}{90}\right)\)
\(=-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\)
=-9/10