\(N=1500\left(nu\right)\Rightarrow10\%N=150\left(nu\right)\)
Theo bài ra ta có hệ: \(\left\{{}\begin{matrix}A-G=150\\2A+2G=1500\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}A=T=450\left(nu\right)\\G=C=300\left(nu\right)\end{matrix}\right.\)
\(\rightarrow\left\{{}\begin{matrix}A=T=\dfrac{450}{1500}.100\%=30\%\\G=C=50\%-30\%=20\%\end{matrix}\right.\)