c, (4 + 1\(\dfrac{3}{5}\)) . 2\(\dfrac{1}{7}\) - 4\(\dfrac{2}{3}\): \(\dfrac{5}{9}\)
= (4 + \(\dfrac{8}{5}\)) . \(\dfrac{15}{7}\) - \(\dfrac{14}{3}\): \(\dfrac{5}{9}\)
= \(\dfrac{28}{5}\). \(\dfrac{15}{7}\) - \(\dfrac{42}{5}\)
= 12 - \(\dfrac{42}{5}\)
= \(\dfrac{18}{5}\)