a: \(=\dfrac{-9}{13}\left(\dfrac{12}{29}+\dfrac{17}{29}\right)+1+\dfrac{11}{13}=\dfrac{-9}{13}+\dfrac{11}{13}+1=1+\dfrac{2}{13}=\dfrac{15}{13}\)
b: \(=\left(\dfrac{5}{3}-\dfrac{2}{11}\right):\dfrac{49}{33}+\dfrac{4}{49}-\dfrac{1}{14}\)
\(=\dfrac{49}{33}\cdot\dfrac{33}{49}+\dfrac{8-7}{98}=\dfrac{99}{98}\)
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