A = \(\left(\dfrac{2}{x-2}+\dfrac{4x}{4-x^2}+\dfrac{x}{x+2}\right):\dfrac{1}{x^2+4x+4}\)
= \(\left(\dfrac{2}{x-2}-\dfrac{4x}{x^2-4}+\dfrac{x}{x+2}\right):\dfrac{1}{\left(x+2\right)^2}\)
= \(\left(\dfrac{2\left(x+2\right)}{x^2-4}-\dfrac{4x}{x^2-4}+\dfrac{x\left(x-2\right)}{x^2-4}\right):\dfrac{1}{\left(x+2\right)^2}\)
= \(\dfrac{2x+4-4x+x^2-2x}{x^2-4}.\left(x+2\right)^2\)
= \(\dfrac{x^2-4x+4}{x^2-4}.\left(x+2\right)^2\)
= \(\dfrac{\left(x-2\right)^2}{x^2-4}.\left(x+2\right)^2\)
= x2 - 4
\(A=\left(\dfrac{2}{x-2}+\dfrac{4x}{4-x^2}+\dfrac{x}{x+2}\right):\dfrac{1}{x^2+4x+4}\)
\(A=\left(\dfrac{2\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}-\dfrac{4x}{\left(x-2\right)\left(x+2\right)}+\dfrac{x\left(x-2\right)}{\left(x+2\right)\left(x-2\right)}\right).\left(x+2\right)^2\)
\(A=\dfrac{2x+4-4x+x^2-2x}{\left(x-2\right)\left(x+2\right)}.\left(x+2\right)^2\)
\(A=\dfrac{\left(x-2\right)^2}{\left(x-2\right)\left(x+2\right)}.\left(x+2\right)^2\)
\(A=\left(x-2\right).\left(x+2\right)=x^2-4\)
A=[2/(x-2)+4x/(4-x2)+x(x+2)]:1/(x2+4x+4)
A=[2(x+2)/(x+2)(x-2)-4x/(x-2)(x+2)+x(x-2)/(x-2)(x+2)]:1/(x+2)2
A=[2(x+2)-4x+x(x-2)/(x+2)(x-2)]:1/(x+2)2
A=[(2x+4-4x+x2-2x)/(x+2)(x-2)]:1/(x+2)2
A=[(x2-4x+4)/(x+2)(x-2)]:1/(x+2)2
A=1/(x+2):1/(x+2)2
A=x+2
Nếu đúng cho 1 like nha <3
giúp em với mn ơi,e đag cần gấp, mn giúp em với ạ
Mn giúp em bài 3 câu bc với em tính số xấu quá, mong mn giúp ạ:(
giúp em với ạ, em đang vội mong mn giúp đỡ
Mn giúp em với ạ, em cần gấp
