Question

m) (x + 2).(3 - x) = 0;        

d) 5¹¹.7¹² + 5¹¹.7¹¹

    5¹².7¹² + 9.5¹¹.7¹¹

q) (x - 3) + (x - 2) + (x - 1) + … + 10 + 11 = 11
r) (x - 3).(2y + 1) = 7;         

s) Tìm x, y thuộc Z sao cho: |x - 8| + |y + 2| = 2;     t) (x + 3).(x2 + 1) = 0.

g. G = 0 – 2 + 4 – 6 + … + 2010 – 2012;      

h. H = 13–12 + 11 + 10 – 9 + 8 – 7 – 6 + 5 – 4 + 3 + 2 – 1
i. I = 1 – 2 – 3 + 4 + 5 – 6 – 7 + 8 + … + 2001 – 2002 – 2003 + 2004

^{giúp minh gấp đc ko mình cần trước 10 giờ cám ơn rất nhiều}

 

Answer 1

Bài làm

m) (x + 2).(3 - x) = 0;     

=> x + 2 = 0 hoặc 3 - x = 0

=> x = -2 hoặc x = 3

Vậy x = -2 hoặc x = 3   

d) 5¹¹.7¹² + 5¹¹.7¹¹ 

= 5¹¹ . ( 7¹² + 7¹¹ )

= 5¹¹ . [ 7¹¹ . ( 7 + 1 ) ]

= 5¹¹ . 7¹¹ . 8

= ( 5 . 7 )¹¹ . 8

= 35¹¹ . 8

5¹².7¹² + 9.5¹¹.7¹¹ 

= 5¹¹ ( 5 . 7¹² + 9 . 1 . 7¹¹ )

= 5¹¹ [ 7¹¹ ( 5 . 7 + 9 . 1 . 1 ) ]

= 5¹¹ ( 7¹¹ . 44 )

= 5¹¹ . 7¹¹ . 44

= 35¹¹ . 44

Answer 2

m.  \(\left(x+2\right)\left(3-x\right)=0\Leftrightarrow\orbr{\begin{cases}x+2=0\\3-x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=3\end{cases}}\)

d. \(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.\left(7^{12}+7^{11}\right)}{5^{11}.\left(5.7^{12}+9.7^{11}\right)}=\frac{7^{12}+7^{11}}{5.7^{12}+9.7^{11}}=\frac{1}{5.9}=\frac{1}{45}\)

q. \(\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+...+10+11=11\)

\(\Rightarrow\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+...+10=0\)

\(\Rightarrow\left[\left(x-3\right)+\left(x-2\right)+\left(x-1\right)\right]+(1+2+3+...+10)=0\)

\(\Rightarrow\left(x-3\right)+\left(x-2\right)+\left(x-1\right)+55=0\)

\(\Rightarrow x-3+x-2+x-1=-55\)

\(\Rightarrow3x-6=-55\)

\(\Rightarrow3x=-49\)

\(\Rightarrow x=-\frac{49}{3}\)

 

Answer 3

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