`|x-3|+5=2x-9`
`@TH1: x-3 >= 0<=>x >= 3 =>|x-3|=x-3`
`=>x-3+5=2x-9`
`<=>x-2x=-9+3-5`
`<=>-x=-11`
`<=>x=11` (t/m)
`@TH2: x-3 < 0<=>x < 3=>|x-3|=3-x`
`=>3-x+5=2x-9`
`<=>-x-2x=-9-3-5`
`<=>-3x=-17`
`<=>x=17/3` (ko t/m)
Vậy `S={11}`
lx - 3l + 5 = 2x - 9
<=> |x - 3| = 2x - 14 (1)
TH1: x ≥ 3 => |x - 3| = x - 3
=> (1) <=> x - 3 = 2x - 14 <=> 11 = x (TM)
TH2: x < 3 => |x - 3| = -(x - 3) = 3 - x
=> (1) <=> 3 - x = 2x - 14 <=> -3x = -17 <=> x = 17/3 (KTM)
vậy x = 11