e, \(=\dfrac{1}{2}x^6y^8-\dfrac{3}{2}x^6y^8=-x^6y^8\)
f, \(=-\dfrac{1}{2}xy^2\left(\dfrac{4}{9}x^4y^2\right)+\dfrac{5}{2}x^5y^4-\dfrac{1}{4}x^4y^2.xy^2=-\dfrac{2}{9}x^5y^4+\dfrac{5}{2}x^5y^4-\dfrac{1}{4}x^5y^4=\dfrac{89}{36}x^5y^4\)
g, \(=-\dfrac{5}{2}x^5y^2+\dfrac{3}{7}.8x^3\left(\dfrac{49}{4}x^2y^2\right)-x^5y^2=-\dfrac{7}{2}x^5y^2+42x^5y^2=\dfrac{77}{2}x^5y^2\)
Tu ti le thuc a/b=c/d(a;b;c;d # 0 ; a # +-b ; c#+-d) hay suy ra các ti le thuc sau : a; a+b/b =c+d/d b; a-b/b=c-d/d c; a+b/a=c+d/c con nhieu nhug ca ban giúp mjh nhieu do thoi lm on nhah nha neu lm het mjh cho các bn 3lik e
Đe bai Phan tích thanh nhan tu
Cau a
X2+xy+ax+ay
Cau b
10a-5by+2ax-bx
Cau c
X(2x-7)-(4x-14)
Cau d
X3-3x2+3x-1-27y3
cac van giúp minh nha minh can gap lam ☺️
Cho tam giac ABC.Qua A ve duong thang xy song song BC,tu M tren canh BC ve cac duong thang song song AB,AC.chung cat xy theo thu tu D vaE
CMR:tam giac ABC=tam giac MDE
Cau b:CMR:ba duong thang AM,BD,CE cat nhau tai 1 diem (dong quy)
Mot nguoi luc si di qua mot cay cau cam them 3 qua ta ,moi qua nang 1 tan va tren cau gan bien bao la cau chi cho vat co can nang tu 2 tan tro xuong . hoi lam sao ma nguoi do qua cau duoc
Voi 8 so 0;1;2;3;4;5;6;7 them tu de duoc cau dung
ba xi nghiep cung xay mot cay cau het 38 trieu dong . xi nghiep 1 co 40 xe o cach cau 1,5 km . xi nghiep 2 co 20 xe o cach cau 3km . xi nghiep 3 co 30 xe o cach cau 1km. hoi moi xi nghiep phai tra cho viec xay cau la ? tien , biet rang so tien phai tra ti le thuan voi so xe va ti le nghich voi khoang cach tu xi nghiep den cau
Ba duong cao cau tam giac ABC co do dai la : 4;12;a.Biết rang a la so tu nhien. Tìm a
Trong cac cau sau day , cau nao dung , cau nao sai ?
a) Neu a la so nguyen thi a cung la so thuc .
b) Chi co so 0 khong la so huu ti duong va cung khong la so huu ti am .
c) Neu a la so tu nhien thi a khong phai la so vo ti .
Online Math oi, sao em da tao va gui hai cau hoi tu tuan truoc ma ko thay dang tren online math vay ???
