\(a,=\left(2\sqrt{3}-\sqrt{3}\right)\sqrt{3}+\sqrt{\dfrac{16}{7}\cdot\dfrac{1}{7}}=3+\dfrac{4}{7}=\dfrac{25}{7}\)
\(b,=\left|\sqrt{2}-3\right|\cdot\sqrt{\left(3+\sqrt{2}\right)^2}=\left(3-\sqrt{2}\right)\left(3+\sqrt{2}\right)=9-2=7\)
a)\(=6-3+\dfrac{4}{7}\)
\(=3+\dfrac{4}{7}=\dfrac{25}{7}\)
b)\(=\left(3-\sqrt{2}\right)\sqrt{\left(\sqrt{2}+3\right)^2}\)
\(=9-2=7\)