Bài 2:
1: \(\Leftrightarrow3\sqrt{x+3}+5\sqrt{x+3}-\dfrac{3}{4}\cdot4\sqrt{x+3}=5\)
\(\Leftrightarrow5\sqrt{x+3}=5\)
=>x+3=1
hay x=-2
2: \(\Leftrightarrow7\sqrt{x-2}-14\cdot\dfrac{\sqrt{x-2}}{7}=3\sqrt{x-2}+8\)
\(\Leftrightarrow2\sqrt{x-2}=8\)
=>x-2=16
hay x=18
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