\(\left(x+\dfrac{5}{9}\right)\times\dfrac{2}{3}=\dfrac{2}{5}=>x+\dfrac{5}{9}=\dfrac{2}{5}:\dfrac{2}{3}=\dfrac{3}{5}=>x=\dfrac{3}{5}-\dfrac{5}{9}=>\dfrac{2}{45}\)
\(\dfrac{3}{5}\times x-\dfrac{3}{2}=\dfrac{5}{6}=>\dfrac{3}{5}\times x=\dfrac{5}{6}+\dfrac{3}{2}=\dfrac{7}{3}=>x=\dfrac{7}{3}:\dfrac{3}{5}=\dfrac{35}{9}\)
\(x-\dfrac{4}{9}=\dfrac{3}{7}:\dfrac{9}{14}=\dfrac{2}{3}=>x=\dfrac{2}{3}+\dfrac{4}{9}=\dfrac{10}{9}\)